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WGU Data Management – Foundations Exam Sample Questions (Q31-Q36):

NEW QUESTION # 31
Which product has an open-source license in addition to having a non-relational system?

A. MongoDB
B. SQL Server
C. Oracle Database
D. MySQL

Answer: A

Explanation:
MongoDB is aNoSQL (non-relational) databasethat isopen-sourceand supportsdocument-oriented storage
. It allows for flexible schema design and is optimized for big data applications.
* Option A (Correct):MongoDB is aNoSQL databasewith an open-sourceAGPLlicense, making it both free to use and non-relational.
* Option B (Incorrect):SQL Serveris arelational database(RDBMS) developed by Microsoft and isnot open-source.
* Option C (Incorrect):MySQLisopen-sourcebut is arelational database(RDBMS), not a NoSQL system.
* Option D (Incorrect):Oracle Databaseisrelationalandproprietary(not open-source).

NEW QUESTION # 32
Which property of an entity can become a column in a table?

A. Modality
B. Attribute
C. Uniqueness
D. Non-null values

Answer: B

Explanation:
Indatabase design,attributesof an entity becomecolumnsin a relational table.
Example Usage:
For anEmployee entity, attributes might include:

CREATE TABLE Employees (
EmployeeID INT PRIMARY KEY,
Name VARCHAR(50),
Salary DECIMAL(10,2),
DepartmentID INT
);
* Eachattribute(e.g., Name, Salary) becomes acolumnin the table.
Why Other Options Are Incorrect:
* Option A (Modality) (Incorrect):Describesoptional vs. mandatoryrelationships, not table structure.
* Option B (Uniqueness) (Incorrect):Ensuresdistinct valuesbutis not a column property.
* Option D (Non-null values) (Incorrect):Ensures thatcolumns must contain databut doesnot define attributes.
Thus, the correct answer isAttribute, as attributes of entities becometable columns.

NEW QUESTION # 33
What is the role of the transaction manager within the database system architecture?

A. The transaction manager logs insert, update, and delete queries, and the result is sent back to the application.
B. The transaction manager uses information from the catalog to perform query optimization.
C. The transaction manager is composed of a query processor, storage manager, transaction manager, log, and catalog.
D. The transaction manager translates the query processor instructions into filesystem commands and uses an index to quickly locate the requested data.

Answer: A

NEW QUESTION # 34
What is the last step in the logical design process for designing a database?

A. Determine cardinality
B. Discover entities
C. Apply a normal form
D. Analyze data requirements

Answer: C

Explanation:
Thelogical design phasein database development focuses onstructuring data efficientlyto eliminate redundancy and ensure integrity. Thefinal step in logical designis toapply normalization (normal forms)to optimize the database schema.
Steps in Logical Database Design:
* Discover entities# Identify real-world objects (e.g., Customers, Orders).
* Determine cardinality# Define relationships between entities (one-to-one, one-to-many).
* Analyze data requirements# Determine the attributes each entity needs.
* Apply normal forms# Eliminate redundancy and improve data consistency.
Example Usage:
* After identifying entities likeStudentsandCourses, applying3rd Normal Form (3NF)ensures that data isorganized without redundancy.
Why Other Options Are Incorrect:
* Option A (Analyze data requirements) (Incorrect):Doneearlierto define attributes.
* Option C (Determine cardinality) (Incorrect):Donebeforenormalization to establish relationships.
* Option D (Discover entities) (Incorrect):Done at thebeginningof database design.
Thus, the correct answer isApply a normal form, as normalization is thelast step in logicaldesign.

NEW QUESTION # 35
How is the primary key indicated in a table?

A. By using a diamond symbol inserted into the table
B. By using a formula in SQL
C. By using bold typeface in the appropriate column
D. By using an SQL keyword

Answer: D

Explanation:
In SQL, aprimary key is explicitly defined using the PRIMARY KEY keywordwhen creating a table.
Example Usage:
sql
CREATE TABLE Products (
ProductID INT PRIMARY KEY,
Name VARCHAR(100),
Price DECIMAL(10,2)
);
* Here,PRIMARY KEY is the SQL keyword that designates ProductID as the primary key.
Why Other Options Are Incorrect:
* Option A (Formula in SQL) (Incorrect):SQLdoes not use formulas to define primary keys.
* Option C (Bold typeface) (Incorrect):SQL syntax does not rely on text formatting.
* Option D (Diamond symbol) (Incorrect):ER diagramsmight use symbols, but SQLdoes not use diamonds to indicate keys.
Thus, the correct answer isSQL keyword, as primary keys are explicitly defined using PRIMARY KEY.

NEW QUESTION # 36
......

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Valid Data-Management-Foundations exam dumps ensure you a high Data-Management-Foundations passing rate

Latest Data-Management-Foundations Test Prep Will Be Your Wisest Choice to Pass WGU Data Management – Foundations Exam

WGU Data Management – Foundations Exam Sample Questions (Q31-Q36):

Top Latest Data-Management-Foundations Test Prep 100% Pass | High-quality Data-Management-Foundations: WGU Data Management – Foundations Exam 100% Pass

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