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SAP C_ABAPD_2309 Exam Syllabus Topics:

Topic	Details
Topic 1	ABAP core data services and data modeling: It focuses on Core Data Services (CDS) views, SAP HANA database tables, foreign key relationships, and annotations.
Topic 2	Core ABAP programming: This topic covers ABAP data types, the ABAP dictionary, modularization, exceptions SAP HANA database tables, and logical expressions, operator precedence.
Topic 3	Object-oriented design: It measures your knowledge about encapsulation, upcast, inheritance, polymorphism, and interfaces. Moreover, the topic evaluates your knowledge about constructor calls, Exception classes, and singleton pattern.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q25-Q30):

NEW QUESTION # 25
What are some properties of database tables? Note: There are 2 correct answers to this question.

A. They can have any number of key fields.
B. They may have key fields.
C. They can have relationships to other tables.
D. They store information in two dimensions.

Answer: C,D

Explanation:
Explanation
Database tables are data structures that store information in two dimensions, using rows and columns. Each row represents a record or an entity, and each column represents an attribute or a field. Database tables may have key fields, which are columns that uniquely identify each row or a subset of rows. Key fields can be used to enforce data integrity, perform efficient searches, and establish relationships to other tables. Database tables can have relationships to other tables, which are associations or links between the key fields of two or more tables. Relationships can be used to model the logical connections between different entities, join data from multiple tables, and enforce referential integrity12.
References: 1: Table (database) - Wikipedia 2: Database design basics - Microsoft Support

NEW QUESTION # 26
Which of the following results in faster access to internal tables? Note: There are 3 correct answers to this question.

A. In a hashed internal table, specifying the primary key partially from the left without gaps.
B. In a hashed internal table, specifying the primary key completely.
C. In a standard internal table, specifying the primary key partially from the left without gaps.
D. In a sorted internal table, specifying the primary key completely.
E. In a sorted internal table, specifying the primary key partially from the left without gaps.

Answer: A,B,D

Explanation:
The access to internal tables can be optimized by using the appropriate table type and specifying the table key.
The table key is a set of fields that uniquely identifies a row in the table and determines the sorting order of the table. The table key can be either the primary key or a secondary key. The primary key is defined by the table type and the table definition, while the secondary key is defined by the user using the KEY statement1.
The following results in faster access to internal tables:
* B. In a sorted internal table, specifying the primary key completely. A sorted internal table is a table type that maintains a predefined sorting order, which is defined by the primary key in the table definition. The primary key can be either unique or non-unique. A sorted internal table can be accessed
* using the primary key or the table index. The access using the primary key is faster than the access using the table index, because the system can use a binary search algorithm to find the row. However, the primary key must be specified completely, meaning that all the fields of the primary key must be given in the correct order and without gaps2.
* D. In a hashed internal table, specifying the primary key partially from the left without gaps. A hashed internal table is a table type that does not have a predefined sorting order, but uses a hash algorithm to store and access the rows. The primary key of a hashed internal table must be unique and cannot be changed. A hashed internal table can only be accessed using the primary key, not the table index. The access using the primary key is very fast, because the system can directly calculate the position of the row using the hash algorithm. The primary key can be specified partially from the left without gaps, meaning that some of the fields of the primary key can be omitted, as long as they are the rightmost fields and there are no gaps between the specified fields.
* E. In a hashed internal table, specifying the primary key completely. A hashed internal table is a table type that does not have a predefined sorting order, but uses a hash algorithm to store and access the rows. The primary key of a hashed internal table must be unique and cannot be changed. A hashed internal table can only be accessed using the primary key, not the table index. The access using the primary key is very fast, because the system can directly calculate the position of the row using the hash algorithm. The primary key can be specified completely, meaning that all the fields of the primary key must be given in the correct order.
The following do not result in faster access to internal tables, because:
* A. In a sorted internal table, specifying the primary key partially from the left without gaps. A sorted internal table is a table type that maintains a predefined sorting order, which is defined by the primary key in the table definition. The primary key can be either unique or non-unique. A sorted internal table can be accessed using the primary key or the table index. The access using the primary key is faster than the access using the table index, because the system can use a binary search algorithm to find the row.
However, the primary key must be specified completely, meaning that all the fields of the primary key must be given in the correct order and without gaps. If the primary key is specified partially from the left without gaps, the system cannot use the binary search algorithm and has to perform a linear search, which is slower2.
* C. In a standard internal table, specifying the primary key partially from the left without gaps. A standard internal table is a table type that does not have a predefined sorting order, but uses a sequential storage and access of the rows. The primary key of a standard internal table is the standard key, which consists of all the fields of the table row in the order in which they are defined. A standard internal table can be accessed using the primary key or the table index. The access using the primary key is slower than the access using the table index, because the system has to perform a linear search to find the row.
The primary key can be specified partially from the left without gaps, but this does not improve the access speed, because the system still has to perform a linear search.
References: 1: Internal Tables - Overview - ABAP Keyword Documentation 2: Sorted Tables - ABAP Keyword Documentation : Hashed Tables - ABAP Keyword Documentation : Standard Tables - ABAP Keyword Documentation

NEW QUESTION # 27
Which function call returns 0?

A. find_any_not_of( val 'ABAP ABAP abap' sub = 'AB')
B. find_any_of (val = "ABAP ABAP abap' sub = "AB")
C. Count_any_of ( val - 'ABAP ABAP abap' sub "AB" )
D. Count (val - 'ABAP ABAP abap' sub - 'AB' )

Answer: A

Explanation:
The function find_any_not_of returns the position of the first character in the string val that is not contained in the string sub. If no such character is found, the function returns 0. In this case, the string val contains only the characters A, B, and a, which are all contained in the string sub, so the function returns 0. The other functions return positive values, as follows:
* Count_any_of returns the number of occurrences of any character in the string sub within the string val.
In this case, it returns 8, since there are 8 A's and B's in val.
* Count returns the number of occurrences of the string sub within the string val. In this case, it returns 2, since there are 2 AB's in val.
* find_any_of returns the position of the first character in the string val that is contained in the string sub.
In this case, it returns 1, since the first character A is in sub. References: String Functions - ABAP Keyword Documentation, Examples of String Functions - ABAP Keyword Documentation

NEW QUESTION # 28
Which of the following actions cause an indirect change to a database table requiring a table conversion? Note: There are 2 correct answers to this question.

A. Changing the field labels of a data element that is used in the table definition.
B. Deleting a field from a structure that is included in the table definition.
C. Renaming a field in a structure that is included in the table definition
D. Shortening the length of a domain used in a data element that is used in the table definition.

Answer: B,C

Explanation:
The following are the explanations for each action:
A: Renaming a field in a structure that is included in the table definition causes an indirect change to the database table, as the field name in the table is derived from the structure. This change requires a table conversion, as the existing data in the table must be copied to a new table with the new field name, and the old table must be deleted.
B: Changing the field labels of a data element that is used in the table definition does not cause an indirect change to the database table, as the field labels are only used for documentation and display purposes. This change does not require a table conversion, as the existing data in the table is not affected by the change.
C: Deleting a field from a structure that is included in the table definition causes an indirect change to the database table, as the field is removed from the table as well. This change requires a table conversion, as the existing data in the table must be copied to a new table without the deleted field, and the old table must be deleted.
D: Shortening the length of a domain used in a data element that is used in the table definition causes an indirect change to the database table, as the field length in the table is derived from the domain. This change requires a table conversion, as the existing data in the table must be checked for compatibility with the new field length, and any data that exceeds the new length must be truncated or rejected.

NEW QUESTION # 29

The "demo_ods_assoc_spfi data source referenced in line #4 contains a field "connid" which you would like to expose in the element list.
Which of the following statements would do this if inserted on line #8?

A. demo_ods_assoc_spfli.connid,
B. demo_ods_assoc_spfli-connid/
C. _spfli.connid/
D. spfli-connid,

Answer: A

Explanation:
The statement that can be used to expose the field "connid" of the data source "demo_ods_assoc_spfli" in the element list is A. demo_ods_assoc_spfli.connid,. This statement uses the dot notation to access the field
"connid" of the data source "demo_ods_assoc_spfli", which is an association defined on line #4. The association "demo_ods_assoc_spfli" links the data source "demo_ods" with the table "spfli" using the field
"carrid". The statement also ends with a comma to separate it from the next element in the list12.
You cannot do any of the following:
* B. demo_ods_assoc_spfli-connid/: This statement uses the wrong syntax to access the field "connid" of the data source "demo_ods_assoc_spfli". The dash notation is used to access the components of a structure or a table, not the fields of a data source. The statement also ends with a slash, which is not a valid separator for the element list12.
* C. spfli-connid,: This statement uses the wrong data source name to access the field "connid". The data source name should be "demo_ods_assoc_spfli", not "spfli". The statement also uses the wrong syntax
* to access the field "connid", as explained above12.
* D. _spfli.connid/: This statement uses the wrong data source name and the wrong separator to access the field "connid". The data source name should be "demo_ods_assoc_spfli", not "_spfli". The statement also ends with a slash, which is not a valid separator for the element list12.
References: 1: ABAP CDS - SELECT, select_list - ABAP Keyword Documentation - SAP Online Help 2: ABAP CDS - SELECT, from - ABAP Keyword Documentation - SAP Online Help

NEW QUESTION # 30
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Best Accurate SAP Latest C_ABAPD_2309 Exam Review - C_ABAPD_2309 Free Download

SAP C_ABAPD_2309 Exam Syllabus Topics:

SAP C_ABAPD_2309 Reliable Test Test & Valid C_ABAPD_2309 Exam Camp

SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q25-Q30):

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